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How Do Hydraulic Rams Generate Force?

 

Squeeze water between your palms. It won’t budge. That resistance—water’s stubborn refusal to compress under pressure—generates the force that lifts 40-ton excavators and powers the $15.7 billion hydraulic cylinder industry.

While electric motors spin and pneumatic systems hiss, hydraulic rams push with brutal efficiency. A construction operator pressing a joystick with 10 pounds of finger pressure can extend a ram delivering 50 tons of force. The multiplication happens not through gears or pulleys, but through a fluid property most people take for granted: incompressibility. This single characteristic, combined with Pascal’s principle discovered in 1653, explains why hydraulic systems dominate industries where raw pushing power matters more than speed—construction equipment alone consumed 35.8% of global hydraulic cylinder output in 2024.

Understanding how hydraulic rams convert fluid pressure into mechanical force requires looking beyond the obvious piston-and-cylinder arrangement. The real mechanism involves pressure transmission, area mathematics, and the stubborn behavior of confined liquids. What follows is the complete physics, from molecular incompressibility to force calculations that determine whether a ram lifts a car or crushes steel.

 

 hydraulic rams
hydraulic rams

 


The Incompressibility Principle: Why Liquids Work and Gases Don’t

 

Hydraulic rams work because liquids refuse to compress. This isn’t a design choice—it’s molecular physics.

The Molecular Lock

When you try to squeeze water in a sealed container, you’re attempting to push molecules closer together. Water molecules at standard pressure sit approximately 3 angstroms apart. To reduce that spacing by even 1%, you need to apply roughly 22,000 PSI—three times the pressure at the deepest point in the ocean. For practical hydraulic pressures (3,000-5,000 PSI), water compresses less than 0.4%. Hydraulic oil, the industry standard, behaves similarly.

Compare this to air. Squeeze air in a cylinder and it collapses readily. Apply 3,000 PSI to a volume of air initially at atmospheric pressure and it compresses to less than 1% of its original volume. This makes air useful for tools requiring fast motion with variable force, but useless for applications demanding consistent, massive pushing power.

Why This Matters for Force Generation

Incompressibility means pressure applied at one point transmits instantly and equally throughout the entire fluid volume. Push a piston into hydraulic fluid with 1,000 PSI, and every square inch of fluid in the system experiences that same 1,000 PSI. No pressure is “lost” to fluid compression. This instant, lossless transmission is what makes force multiplication possible.

The 2021 MDPI study on hydraulic cylinder failures emphasizes this: 41.1% of all cylinder failures trace back to fluid contamination introducing compressible air bubbles. Even 5% air contamination reduces force output by 15-20% and creates “spongy” ram behavior as the compressible air absorbs pressure instead of transmitting it.

 

 


Pascal’s Principle: The Mathematical Foundation

 

In 1653, French mathematician Blaise Pascal observed that pressure applied to confined fluid distributes uniformly throughout the fluid. This observation, now called Pascal’s principle, provides the mathematical framework for every hydraulic ram.

The Core Formula

Pascal’s principle states:

P₁ = P₂

Where pressure equals force divided by area:

F₁/A₁ = F₂/A₂

Rearranged for force multiplication:

F₂ = F₁ × (A₂/A₁)

This equation reveals the key insight: output force depends entirely on the ratio of piston areas, not on cylinder size, fluid type, or operating temperature.

A Concrete Example

Consider a hydraulic jack lifting a 2,000 kg car:

  • Input piston diameter: 2 cm (area = 3.14 cm²)
  • Output piston diameter: 20 cm (area = 314 cm²)
  • Area ratio: 314/3.14 = 100:1

The car’s weight generates a force of approximately 19,600 N (2,000 kg × 9.8 m/s²). To support this, the input force needed is:

F₁ = 19,600 N / 100 = 196 N

That’s roughly 44 pounds—the force of a firm handshake. The jack multiplies this 100-fold through area ratio alone.

Pressure Throughout the System

The fluid pressure in this example is:

P = F₁/A₁ = 196 N / 3.14 cm² = 62.4 N/cm² = 6.24 MPa (905 PSI)

This same 905 PSI exists everywhere in the hydraulic system: in the input cylinder, the output cylinder, and every connecting pipe. The pressure doesn’t “build up” or “decrease”—it’s constant throughout, as Pascal predicted 372 years ago.

 

 


The Force Multiplication Framework: Three Dimensions of Ram Design

 

Hydraulic ram force generation operates across three interrelated dimensions, forming what I call the Hydraulic Force Triangle:

           Pressure
          /      \
         /        \
    Force  ←→  Area

Every ram design represents a deliberate choice about which two vertices to prioritize, as you cannot maximize all three simultaneously.

Dimension 1: Pressure Ceiling

Industrial hydraulic systems typically operate at:

  • Standard duty: 3,000 PSI (20.7 MPa)
  • Heavy duty: 5,000 PSI (34.5 MPa)
  • Specialized applications: 10,000+ PSI (69+ MPa)

Higher pressure allows smaller cylinders for a given force, but requires:

  • Stronger cylinder walls (increasing weight and cost)
  • Better seals (higher failure risk)
  • More robust fittings (complexity)

A 5,000 PSI system delivers 67% more force than a 3,000 PSI system with identical cylinder dimensions, but component costs increase roughly 120-150%.

Dimension 2: Effective Area

The force-generating area is the piston face in contact with pressurized fluid. For a 100 mm bore cylinder:

  • Area = π × (50 mm)² = 7,854 mm² = 78.54 cm²

At 3,000 PSI (207 bar), this generates:

  • Force = 207 bar × 78.54 cm² = 16,260 N (3,655 pounds)

Double the bore to 200 mm:

  • Area increases 4× to 314 cm²
  • Force quadruples to 65,040 N (14,620 pounds)

This quadratic relationship between diameter and force explains why heavy construction equipment uses 150-250 mm bore cylinders despite the weight penalty.

Dimension 3: Stroke Length

Stroke determines how far the ram extends. Unlike pressure and area, stroke doesn’t affect maximum force—but it fundamentally limits what tasks the ram can perform.

A ram generating 10 tons of force with:

  • 10 cm stroke: Can crush materials, not move them far
  • 100 cm stroke: Can lift objects through useful distances
  • 500 cm stroke (telescopic): Can extend boom arms on cranes

The trade-off: longer strokes require proportionally longer cylinders or complex telescoping mechanisms, increasing cost and reducing mechanical efficiency by 5-8% per telescoping stage.

 

 


Inside the Hydraulic Ram: Anatomy of Force Conversion

 

A working hydraulic ram comprises seven essential components, each critical to force generation:

1. Cylinder Barrel

The barrel contains pressurized fluid and must withstand hoop stress—circumferential stress trying to burst the cylinder like an over-inflated balloon. For a 100 mm bore cylinder at 5,000 PSI with 10 mm wall thickness:

Hoop stress = (Pressure × Radius) / Wall Thickness = (345 bar × 50 mm) / 10 mm = 1,725 bar (25,000 PSI)

High-strength steel with 800+ MPa yield strength handles this, but the barrel typically accounts for 40-50% of the ram’s total weight.

2. Piston

The piston separates two pressure chambers and transfers fluid pressure into linear force on the rod. Double-acting cylinders (70% of the 2024 market) use pistons with seals on both sides, allowing force generation during both extension and retraction.

Piston design affects efficiency. A well-designed piston with low-friction seals operates at 90-95% efficiency. Poor piston design with excessive seal friction drops this to 75-80%, meaning 20-25% of input hydraulic power converts to waste heat instead of useful work.

3. Piston Rod

The rod extends from the piston through the cylinder head and applies force to the load. Rod diameter matters for buckling strength. For a 4-meter-long ram with 50 mm rod diameter supporting 10,000 N:

Euler buckling load = (π² × E × I) / L²

Where E = material stiffness (200 GPa for steel) and I = moment of inertia. This particular configuration has a safety factor of approximately 3.2—acceptable for most applications, inadequate for side-loaded scenarios.

Side loading—force applied perpendicular to rod axis—is the leading mechanical cause of cylinder failure. Even 5° misalignment can reduce seal life by 60% and accelerate rod wear 10-fold.

4. Cylinder Head and Cap

These end caps seal the cylinder barrel and contain the rod guiding system. The head (rod end) experiences both pressure stress and bending loads from rod forces. Poor head design allows microscopic flexing that wears seals and reduces efficiency.

5. Seals

Seals prevent fluid leakage while allowing rod movement. A standard ram uses four seal types:

  • Piston seals: Hold pressure differential across piston
  • Rod seals: Prevent external leakage at rod exit
  • Wiper seals: Block contaminants from entering
  • Wear bands: Guide piston and rod, preventing metal-to-metal contact

Seal failure accounts for 35-40% of hydraulic ram maintenance costs. Modern polyurethane seals last 2-3 years under normal conditions; contaminated oil reduces this to 6-12 months.

6. Ports

Inlet and outlet ports allow fluid flow into and out of pressure chambers. Port sizing affects flow restriction. Undersized ports create pressure drop, reducing maximum force by 5-10% and generating heat. The rule of thumb: port diameter should be at least 60% of the maximum flow pipe diameter.

7. Mounting Hardware

Clevis mounts, trunnions, and flanges transfer ram force to the machine structure. Mounting design determines whether ram force applies purely axially (efficient, long-lasting) or includes bending moments (causes premature failure).

A 100,000 N ram with 10° mounting misalignment experiences:

  • Axial force: 98,500 N
  • Side force: 17,400 N

That 17,400 N side load can crack mounting brackets or destroy seals in weeks.

 

 


The Hydraulic System: How Rams Connect to Power

 

Rams don’t generate force in isolation. They’re part of a complete hydraulic circuit that includes:

Hydraulic Pump: The Force Generator

Pumps don’t “create pressure”—they create flow. Pressure develops when that flow meets resistance (the load). A pump rated for 10 gallons per minute pushing against a ram extending at 2 inches per second generates whatever pressure is necessary to move the load at that speed, up to the system’s maximum.

Common pump types:

  • Gear pumps: Simple, cheap, 80-85% efficient, noisy
  • Vane pumps: Quieter, 85-90% efficient, moderate cost
  • Piston pumps: 95%+ efficient, expensive, handles high pressure

The global hydraulic cylinder market of $15.7 billion in 2024 relies heavily on these pumps, with piston pumps dominating construction equipment (35.8% market share) due to their high-pressure capabilities.

Valves: Force Control Systems

Directional control valves route fluid to extend or retract the ram. Pressure relief valves prevent over-pressurization that would burst cylinders or rupture hoses. Flow control valves govern ram speed.

A ram extending too fast with light load can cavitate—forming vacuum bubbles that implode violently, creating shock waves that damage components. Proper valve timing prevents this, but adds cost and complexity.

Reservoir and Filters

The reservoir stores fluid and allows heat dissipation. Hydraulic systems convert 10-25% of input power to heat. A 50 kW hydraulic system may generate 5-12 kW of waste heat that must dissipate to avoid fluid breakdown.

Filters remove contaminants. The 41.1% failure rate from contamination mentioned earlier drops to under 5% with proper filtration. Industry standard: 10-micron filters changed every 500 operating hours, with fluid analysis every 1,000 hours.

 

 


Force Output Calculations: Predicting Ram Performance

 

Theoretical maximum force from a hydraulic ram is:

F = P × A

Where:

  • F = force (Newtons or pounds)
  • P = pressure (Pa or PSI)
  • A = effective piston area (m² or in²)

Example 1: Mobile Equipment Ram

  • Bore: 100 mm (effective area: 78.54 cm²)
  • Rod: 56 mm (rod-side area: 78.54 – 24.63 = 53.91 cm²)
  • Pressure: 250 bar (3,625 PSI)

Extension force (full bore): 250 bar × 78.54 cm² = 19,635 N (4,414 pounds)

Retraction force (annular area): 250 bar × 53.91 cm² = 13,478 N (3,030 pounds)

Note the 31% force reduction on retraction due to the rod area reducing effective piston area.

Example 2: Heavy Construction Ram

  • Bore: 200 mm (effective area: 314 cm²)
  • Pressure: 350 bar (5,076 PSI)

Force: 350 bar × 314 cm² = 109,900 N (24,700 pounds or 12.35 tons)

This explains excavator lifting capacity. A typical 40-ton excavator uses 6-8 such rams working in combination to generate 200,000+ N of bucket breakout force.

Efficiency Losses

Real-world force is 85-95% of theoretical maximum due to:

  • Seal friction: 2-5% loss
  • Internal leakage: 1-3% loss
  • Rod seal friction: 1-2% loss
  • Bearing friction: 1-2% loss
  • Fluid viscosity: 0-3% loss (temperature dependent)

A “90% efficient” ram generating 100,000 N theoretical force delivers 90,000 N actual force. The missing 10,000 N converts to heat in seals and fluid.

 

 


Double-Acting vs. Single-Acting Rams: Design Philosophy

 

Double-Acting Rams: Powered Both Ways

These rams use hydraulic pressure for both extension and retraction. Fluid ports on both sides of the piston allow force generation in both directions.

Advantages:

  • Controlled retraction under load
  • Faster cycle times (no waiting for gravity/springs)
  • Bidirectional positioning capability
  • Represents 70% of 2024 market share

Retraction force is always less than extension force due to rod area reducing effective piston area on the retraction side. For a 100 mm bore, 56 mm rod cylinder, retraction force is approximately 68% of extension force.

Single-Acting Rams: Gravity Return

These rams use hydraulic pressure only for extension. Retraction occurs via gravity, spring force, or external load. The cylinder has one pressure port and an air vent on the opposite side.

Advantages:

  • Simpler design, fewer failure points
  • Lower cost (30-40% less than equivalent double-acting)
  • Lighter weight
  • Ideal for vertical lifting applications

Disadvantages:

  • No controlled retraction force
  • Slower cycle times
  • Cannot pull loads
  • Limited to applications where gravity or external force provides return

Common in hydraulic jacks, presses, and clamping fixtures where precise retraction control is unnecessary.

 

 


Telescoping Rams: Multi-Stage Force Multiplication

 

Telescoping (telescopic) cylinders extend to many times their closed length by nesting multiple stages. A four-stage telescoping ram might extend from 1.5 meters closed to 6 meters fully extended.

How Telescoping Affects Force

Each stage has progressively smaller diameter:

  • Stage 1 (largest): 200 mm bore
  • Stage 2: 170 mm bore
  • Stage 3: 140 mm bore
  • Stage 4: 110 mm bore

At 250 bar pressure:

  • Stage 1 force: 78,500 N
  • Stage 2 force: 56,750 N
  • Stage 3 force: 38,500 N
  • Stage 4 force: 23,750 N

Force decreases 70% from first to last stage. Dump trucks and mobile cranes using telescoping rams must account for this—lifting capacity drops dramatically as the ram extends.

Trade-offs

Telescoping rams solve the space problem (long stroke in compact package) but introduce complexity. Each stage adds:

  • 5-8% efficiency loss
  • Additional seal surfaces (more potential leak points)
  • 20-25% cost increase
  • Slightly reduced reliability (more components to fail)

The global market shows telescoping rams growing at 6.9% annually, fastest of all cylinder types, driven by mobile equipment demand where compactness matters.

 

 hydraulic rams
hydraulic rams

 


Common Failure Modes: When Force Generation Breaks Down

 

Fluid Contamination (41.1% of failures)

Particles in hydraulic fluid act like sandpaper inside the cylinder. Contamination above 25 microns accelerates seal wear 50-100 fold. Over time:

  • Seals develop scratches allowing internal leakage
  • Leakage reduces pressure across the piston
  • Force output drops proportionally with pressure loss

A ram losing 10% of pressure through internal leakage loses 10% of force output. At 30% leakage, the ram becomes effectively useless despite appearing to function.

Solution: 10-micron filtration, monthly fluid samples, sealed breathers to prevent ingress.

Seal Failure (35-40% of maintenance costs)

Damaged seals cause external leakage (visible oil drips) or internal leakage (pressure bypass). Internal leakage is insidious—the ram appears to work but delivers progressively less force as seals degrade.

Seal life depends heavily on side loading. A perfectly aligned ram might achieve 2,000,000 cycles; 5° misalignment reduces this to 200,000 cycles—a 90% reduction.

Rod Damage and Scoring

Chrome-plated piston rods resist corrosion and wear. Scratches in the chrome allow rust formation. When the ram retracts, the rusty rod destroys the rod seal, causing leakage.

Cylinder bore scoring—scratches on the internal cylinder wall—creates similar problems. Contamination is the usual culprit; a single piece of metal grit can score the entire bore in one stroke, permanently damaging the cylinder.

Cavitation

When rams move too fast or during rapid directional changes, local pressure drops below vapor pressure and the fluid “boils,” forming bubbles. When bubbles collapse, they generate shock waves exceeding 10,000 PSI locally—enough to pit metal and destroy seals.

Cavitation sounds like gravel inside the cylinder and reduces ram life by 60-80%. Prevention requires properly sized valves and controlled acceleration/deceleration rates.

Air Entrapment

Even small amounts of air (2-3% by volume) create “spongy” ram behavior. The ram extends and retracts with noticeable hesitation as compressible air absorbs pressure before incompressible fluid transmits it.

Bleeding air from hydraulic systems is routine maintenance. High-point bleed valves allow trapped air to escape, restoring normal force transmission.

 

 


Frequently Asked Questions

 

How much force can hydraulic rams generate?

Force equals pressure times effective area. A 200 mm bore cylinder at 5,000 PSI generates approximately 25,000 pounds (11.3 metric tons). Specialized high-pressure rams exceed 500 tons. The limiting factor is cylinder strength—steel can only withstand so much pressure before failing.

Why do hydraulic systems use oil instead of water?

Water corrodes steel components and freezes at 0°C. Hydraulic oil provides lubrication (reducing friction), rust protection, and operates from -40°C to +120°C. However, bio-based hydraulic fluids are gaining market share (8-10% annual growth) for environmental applications.

Can hydraulic rams push and pull with equal force?

No. Double-acting rams pull with less force than they push because the rod occupies space on the retraction side, reducing effective area. A 100 mm bore, 56 mm rod cylinder generates 68% as much retraction force as extension force. Single-acting rams don’t pull at all.

What’s the difference between hydraulic rams and pneumatic cylinders?

Hydraulic systems use incompressible oil; pneumatic systems use compressible air. Hydraulics generate 10-20 times more force for equivalent cylinder size but move slower. Pneumatics excel at high-speed applications with lighter loads. Cost is similar, but hydraulics require more maintenance due to fluid containment requirements.

How fast can hydraulic rams move?

Speed equals flow rate divided by piston area. A 100 mm bore cylinder receiving 10 liters/minute extends at approximately 21 mm/second (1.3 meters/minute). Faster speeds require higher flow rates, which increase pump power and generate more heat. Most industrial rams operate at 5-30 cm/second.

Do bigger hydraulic rams always generate more force?

At the same pressure, yes—force scales with area, which scales with diameter squared. But pressure varies by application. A 50 mm cylinder at 5,000 PSI may generate more force than a 100 mm cylinder at 1,000 PSI. The key equation remains: Force = Pressure × Area.

Why do hydraulic systems lose force over time?

Progressive seal wear allows internal leakage. Fluid bypasses the piston instead of pushing it. A ram with 20% internal leakage generates only 80% of its rated force. Regular seal replacement (every 2-5 years depending on usage) maintains force output.

 


Maximizing Ram Force Output: Engineering Best Practices

 

1. Optimize Pressure for Application

Don’t over-pressurize. Higher pressure increases force but accelerates wear and risks catastrophic failure. Match system pressure to actual force requirements plus 20% safety margin. A task needing 20,000 N continuous force with a 100 mm bore ram requires:

Pressure = Force / Area = 20,000 N / 78.54 cm² = 255 bar

Specify 300 bar system pressure (20% margin) rather than maximum 400+ bar capability. Component life increases 40-60% at moderate pressures.

2. Ensure Perfect Alignment

Every degree of misalignment shortens seal life exponentially. Install rams with spherical rod-end bearings allowing 3-5° of angular misalignment without loading the rod sideways. Use alignment tools during installation—visual alignment is insufficient.

3. Control Fluid Cleanliness

Install 10-micron return-line filters and 25-micron pressure-line filters. Sample fluid every 1,000 hours, targeting ISO 16/14/11 cleanliness or better. Contamination is 41.1% of failures; filtration is 90% of the solution.

4. Manage Heat

Hydraulic systems operating above 65°C degrade seals and fluid. Install oil coolers if continuous operation is required. Size the reservoir for at least 3x pump flow rate (in liters per minute) to allow heat dissipation time.

5. Bleed Air Religiously

After any hydraulic work, cycle the ram through full extension/retraction 3-5 times while cracking bleed valves at high points. Air-free systems respond instantly and generate full rated force.

6. Select Appropriate Cylinder Type

  • Heavy loads with precise control: Double-acting welded cylinders
  • Weight-sensitive mobile equipment: Double-acting tie-rod cylinders
  • Simple vertical lifting: Single-acting rams
  • Long reach requirements: Telescoping cylinders (accepting force reduction)

The 2024 market breakdown shows welded cylinders at 53.4% market share for good reason—they handle higher pressures with better sealing.

 


The Future of Hydraulic Force Generation

 

The $15.7 billion hydraulic cylinder market (2024) is projected to reach $24.7 billion by 2034 at 4.6% CAGR. Several trends are reshaping how rams generate and apply force:

Electrification Pressure

Electric actuators are capturing 3-5% annual market share in precision applications. Electric actuation offers positioning accuracy to 0.01 mm and doesn’t leak. However, hydraulics still dominate where brute force matters—electric actuators generating 50+ tons remain impractical.

The compromise: Hybrid systems using electric pumps with variable speed drives. These improve efficiency 15-25% over constant-speed hydraulic pumps while maintaining hydraulic force density.

Smart Cylinders with Embedded Sensors

Position sensors, pressure transducers, and temperature monitors embedded in rams enable predictive maintenance. Systems detect seal degradation 1,000-2,000 operating hours before failure by monitoring internal leakage rates. This prevents unexpected force loss and allows scheduled seal replacement during planned downtime.

Higher Pressure Systems

Some manufacturers are pushing to 7,000-10,000 PSI (480-690 bar) for mobile equipment. This allows 40% smaller, lighter cylinders for equivalent force. Challenges include seal materials—conventional polyurethane fails above 6,000 PSI—and safety concerns with stored energy in high-pressure systems.

Bio-Based Hydraulic Fluids

Environmental regulations are driving adoption of biodegradable fluids, particularly in forestry and agriculture where leakage impacts soil. These fluids match petroleum performance but degrade 90% within 21 days of environmental release. Market share reached 8% in 2024, projected for 15% by 2030.

 


Conclusion: The Enduring Power of Incompressible Force

 

Hydraulic rams work because liquids refuse to compress. This single physical fact, combined with Pascal’s 372-year-old observation about pressure transmission, creates force multiplication that spans from 10-ton hydraulic jacks to 500-ton industrial presses.

The math is straightforward: Force equals pressure times area. The engineering is complex: managing contamination, preventing leaks, ensuring alignment, and controlling heat all determine whether a ram generates its theoretical force or falls short. The 41.1% failure rate from contamination alone proves that force generation depends as much on fluid cleanliness as on cylinder diameter.

As the hydraulic cylinder market grows from $15.7 billion to $24.7 billion by 2034, the fundamental physics remains unchanged. Liquids still won’t compress. Pascal’s principle still governs pressure distribution. And hydraulic rams will continue generating the massive pushing force that makes modern construction, manufacturing, and agriculture possible.

The next time you see an excavator lifting tons of earth or a hydraulic press forming steel, remember: that force starts with the stubborn incompressibility of fluid and multiplies through the elegant mathematics of area ratios. Simple physics. Extraordinary power.

 

 hydraulic rams
hydraulic rams

 


Key Takeaways

  • Hydraulic rams generate force by applying pressure to incompressible fluid across a large piston area, multiplying input force by the area ratio
  • Force output equals pressure (PSI or bar) times effective piston area; doubling cylinder diameter quadruples force
  • Real rams achieve 85-95% efficiency due to seal friction, with internal leakage being the primary cause of force degradation over time
  • 41.1% of cylinder failures trace to fluid contamination, making filtration and fluid cleanliness critical to maintaining force output
  • Double-acting cylinders dominate the market (70% share) for their bidirectional force capability, though retraction force is typically 60-70% of extension force

Data Sources

  1. GM Insights – Hydraulic Cylinder Market Size Report, 2025-2034
  2. Research Nester – Hydraulic Cylinder Market Report, 2025-2037
  3. MDPI – Hydraulic Cylinder Failure Analysis Study, 2021
  4. Grand View Research – Hydraulic Cylinder Industry Analysis, 2024
  5. Physics LibreTexts – Pascal’s Principle and Hydraulics
  6. GeeksforGeeks – Pascal’s Law: Formula, Derivation, and Applications
  7. Cylinders Inc. – 9 Most Common Causes of Hydraulic Cylinder Failure
  8. Enerpac – Pascal’s Law and Hydraulic Tools Technical Guide